TRONG KHÔNG GIAN VỚI HỆ TỌA ĐỘ $ OXYZ$, CHO TAM GIÁC $ ABC$ VỚI $ A\LEFT( {1; – 3;4} \RIGHT),B\LEFT( { – 2; – 5; – 7} \RIGHT)$, $ C\LEFT( {6; – 3; – 1} \RIGHT)$. PHƯƠNG TRÌNH ĐƯỜNG TRUNG TUYẾN $ AM$ CỦA TAM GIÁC LÀ:
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- $ \\\left\\\{ \\\begin{gathered} x = 1 + t \\\hfill \\\\\\ y = - 3 - t \\\hfill \\\\\\ z = 4 - 8t \\\hfill \\\\\\ \\\end{gathered} \\\right.\\\,\\\,\\\,\\\,\\\,\\\,\\\,\\\,\\\,\\\,t \\\in \\\mathbb{R}$.
- $ \\\left\\\{ \\\begin{gathered} x = 1 + t \\\hfill \\\\\\ y = - 1 - 3t \\\hfill \\\\\\ z = - 8 - 4t \\\hfill \\\\\\ \\\end{gathered} \\\right.\\\,\\\,\\\,\\\,\\\,\\\,\\\,\\\,\\\,\\\,t \\\in \\\mathbb{R}$.
- $ \\\left\\\{ \\\begin{gathered} x = 1 + 3t \\\hfill \\\\\\ y = - 3 + 4t \\\hfill \\\\\\ z = 4 - t \\\hfill \\\\\\ \\\end{gathered} \\\right.\\\,\\\,\\\,\\\,\\\,\\\,\\\,\\\,\\\,\\\,t \\\in \\\mathbb{R}$.
- $ \\\left\\\{ \\\begin{gathered} x = 1 - 3t \\\hfill \\\\\\ y = - 3 - 2t \\\hfill \\\\\\ z = 4 - 11t \\\hfill \\\\\\ \\\end{gathered} \\\right.\\\,\\\,\\\,\\\,\\\,\\\,\\\,\\\,\\\,\\\,t \\\in \\\mathbb{R}$.