ĐẶT $ I = \INT\LIMITS_0^{\FRAC{\PI }{2}} {X\SIN XDX}$ VÀ $ J = \INT\LIMITS_0^{\FRAC{\PI }{2}} {{X^2}CO{\MATHOP{\RM S}\NOLIMITS} XDX}$ . KHẲNG ĐỊNH NÀO SAU ĐÂY ĐÚNG?
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Level:
Medium
Question Types: Multiple choice
Answers:
- $ J = \\\frac{{{\\\pi ^2}}}{4} + 2I.$
- $ J = - \\\frac{{{\\\pi ^2}}}{4} - 2I.$
- $ J = \\\frac{{{\\\pi ^2}}}{4} - 2I.$
- $ J = - \\\frac{{{\\\pi ^2}}}{4} + 2I.$