CHO $ F(X) = \INT {(X + 1)\SIN X\;DX} .$ ĐẶT $ \LEFT\{ \BEGIN{ARRAY}{L} U = X + 1\\ DV = \SIN XDX \END{ARRAY} \RIGHT.$ , TA CÓ : $ \LEFT\{ \BEGIN{ARRAY}{L} DU = 1.DX\\ V = – \COS X \END{ARRAY} \RIGHT..$ MỆNH ĐỀ NÀO SAU ĐÂY LÀ ĐÚNG?
Want to know the answer? Start playing now!
Level:
Medium
Question Types: Multiple choice
Answers:
- $ F(x) = (x + 1)( - \\\cos x) + \\\int {\\\cos x\\\;dx} .$
- $ F(x) = (x + 1)( - \\\cos x) - \\\int {\\\cos x\\\;dx} .$
- $ F(x) = (x + 1)( - \\\cos x) - \\\int {\\\sin x\\\;dx} .$
- $ F(x) = (x + 1)\\\sin x + \\\int {\\\cos x\\\;dx} .$