CHO $ \INT\LIMITS_0^1 {\FRAC{{D{\RM{X}}}}{{\SQRT {X + 2} + \SQRT {X + 1} }}} = A\SQRT B – \FRAC{8}{3}\SQRT A + \FRAC{2}{3}\LEFT( {A,B \IN {N^*}} \RIGHT).$ TÍNH $ A + 2B$
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Level:
Medium
Question Types: Multiple choice
Answers:
- $ a + 2b = 5$
- $ a + 2b = 8$
- $ a + 2b = 7$
- $ a + 2b = - 1$